im seeing alot of this on different boards.Can phs be converted into real test or other aas?
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pro-hormone conversion?
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Yes they can be converted to a sterile solution just as you would any other hormone powder. That will not make it a steroid because of the esters and chemical make up of the powders. Pro hormones are that pro hormones. Some are more difficult to convert but is possable.
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If I'm understanding you correctly, you're saying PH's can't be converted to steroids. That isn't correct. PH's differ from steroids because they use naturaly occuring enzymes to convert in the liver to a target hormone. IOW, PH's aren't anabolicly active in their initial state. Steroids, however, are. Like spidey said, it depends on what you know. PH's can be converted into steroids and through saphonificatoin, have an ester added to them as well.Originally posted by Big Tex
Yes they can be converted to a sterile solution just as you would any other hormone powder. That will not make it a steroid because of the esters and chemical make up of the powders. Pro hormones are that pro hormones. Some are more difficult to convert but is possable.
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I think you mean oxidation. Saponification is the hydrolysis of an ester under basic conditions.Originally posted by candle25
If I'm understanding you correctly, you're saying PH's can't be converted to steroids. That isn't correct. PH's differ from steroids because they use naturaly occuring enzymes to convert in the liver to a target hormone. IOW, PH's aren't anabolicly active in their initial state. Steroids, however, are. Like spidey said, it depends on what you know. PH's can be converted into steroids and through saphonificatoin, have an ester added to them as well.
Oxidizing the 3-OH of 4-androstenediol gives testosterone for example.
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Oxidizing the 3-OH of 4-androstenediol gives TNE.
C19H30O2 + MnO2 ---> C19H28O2 + MnO + H2O
(Molecular Formula for Reaction)
In this reaction MnO2 is used as an oxidizer to remove the two H from the single O at the end of the hexane ring. MnO2 is also the excess reagent in the reaction. Chloroform acts as the solvent for the 4AD & the Test because it will not dissolve the MnO2 or MnO.
In order to add an ester you'd just take the TNE and add 1)MeOH, NaOH & 2)H2O. So wouldn't that be oxidation then saphonification?
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That's not the way to add an ester to test base. First, where is the carboxylic acid you are putting on the 17-OH to make an ester? Second, you can't make an ester under aqueous base conditions. That is how one CLEAVES an ester, not makes one. And no, making an ester is not an oxidation. Look up the term "saponification" in an organic text book; it is the basic hydrolysis of an ester.Originally posted by candle25
Oxidizing the 3-OH of 4-androstenediol gives TNE.
C19H30O2 + MnO2 ---> C19H28O2 + MnO + H2O
(Molecular Formula for Reaction)
In this reaction MnO2 is used as an oxidizer to remove the two H from the single O at the end of the hexane ring. MnO2 is also the excess reagent in the reaction. Chloroform acts as the solvent for the 4AD & the Test because it will not dissolve the MnO2 or MnO.
In order to add an ester you'd just take the TNE and add 1)MeOH, NaOH & 2)H2O. So wouldn't that be oxidation then saphonification?
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