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  • chemistry question

    Does anyone know how to do this problem? I dont have any idea how to do it since I missed the lecture on this chapter when I was buying the new xbox, and the chem tutor only works on tuesdays/thursdays. I have to do a power point presentation on it tommorow, so I need to be sure its correct which im not :thumbsdow

    Here is the question,

    A sealed balloon has a volume of 50.cm^3 when filled with air at 22.0 C and atmospheric pressure. The air in the balloon is heated. Assuming that the pressure remains constant, at what temperature does the volume of the balloon become 60.0 cc?

    :hmmm:

  • #2
    Originally posted by FitnessBrat
    Lol, I love the "I missed the lecture because I was buying the new xbox"
    lol, I know, that sounds like such a slacker but its true :(
    Last edited by rude; 11-28-05, 05:10 PM.

    Comment


    • #3
      The answer is 81 degrees C.

      To solve it you use the ideal gas law (that is assuming that the gas in the question is an ideal gas, which you didn't specify). The law states PV=nRT.
      n=number of moles of the gas
      R= the universal gas constant
      Both of these don't change for the gas in the balloon, so they are both constants, as is P because it is specified as such in the equation.

      This gives you V/T = V'/T'

      The ideal gas law requires that temperature is in Kelvin, so 22 + 273.15 = 295.15 K

      This leaves us with 50cc/295.15K = 60cc/?
      Yields---> 354.18K

      If you want it in celsius 354.18-273.15 = 81.03 C

      Comment


      • #4
        Originally posted by Severedties
        The answer is 81 degrees C.

        To solve it you use the ideal gas law (that is assuming that the gas in the question is an ideal gas, which you didn't specify). The law states PV=nRT.
        n=number of moles of the gas
        R= the universal gas constant
        Both of these don't change for the gas in the balloon, so they are both constants, as is P because it is specified as such in the equation.

        This gives you V/T = V'/T'

        The ideal gas law requires that temperature is in Kelvin, so 22 + 273.15 = 295.15 K

        This leaves us with 50cc/295.15K = 60cc/?
        Yields---> 354.18K

        If you want it in celsius 354.18-273.15 = 81.03 C

        Awesome, had no idea what formula to use or anything. Thanks, now i'll look smart at my presentation tommorow morning :P

        Comment


        • #5
          http://hyperphysics.phy-astr.gsu.edu...c/idegasc.html


          And tell your teacher he/she is a prick for putting different units in there when they really are equal....

          And I agree with the above answer! :agree:

          Comment


          • #6
            you guys make me want to go back to school. :)

            Comment


            • #7
              :nerdnew: <---- Severedties
              Originally posted by Severedties
              The answer is 81 degrees C.

              To solve it you use the ideal gas law (that is assuming that the gas in the question is an ideal gas, which you didn't specify). The law states PV=nRT.
              n=number of moles of the gas
              R= the universal gas constant
              Both of these don't change for the gas in the balloon, so they are both constants, as is P because it is specified as such in the equation.

              This gives you V/T = V'/T'

              The ideal gas law requires that temperature is in Kelvin, so 22 + 273.15 = 295.15 K

              This leaves us with 50cc/295.15K = 60cc/?
              Yields---> 354.18K

              If you want it in celsius 354.18-273.15 = 81.03 C

              Comment


              • #8
                Rude: No problem.
                Shibby: :madfu:
                You know me... lol

                Comment


                • #9
                  Originally posted by stonecold54
                  you guys make me want to go back to school. :)
                  They make me feel stupid. My brain hurts from reading that.

                  Comment


                  • #10
                    How about you tell your teacher that you used the ideal gas equation because you assumed it was an ideal gas and YOU WOULD HAVE used the Peng-Robinson or Redlich-Kuang-Suave if it wasn't an ideal gas. :D

                    Comment


                    • #11
                      Lol. It is certainly an ideal gas equation. No way they got to peng-robinson in a single lecture. Especially if he has to give a presentation on solving the problem.

                      Comment


                      • #12
                        Originally posted by Severedties
                        Lol. It is certainly an ideal gas equation. No way they got to peng-robinson in a single lecture. Especially if he has to give a presentation on solving the problem.
                        Have you decided which direction you want to take, DNA, Plastic surgery...?

                        Comment


                        • #13
                          Originally posted by Severedties
                          Lol. It is certainly an ideal gas equation. No way they got to peng-robinson in a single lecture. Especially if he has to give a presentation on solving the problem.

                          He could say he read ahead LoL! :nerdnew:

                          Comment


                          • #14
                            Originally posted by stonecold54
                            you guys make me want to go back to school. :)
                            makes me damn glad im in accounting and never have to even look at chem

                            Comment


                            • #15
                              Originally posted by Lmg2701
                              He could say he read ahead LoL! :nerdnew:
                              lol. Might get a laugh.

                              Comment

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